2014华为机试第一题：字符串补0输出

题目描述：按要求分解字符串，输入两个数M，N；M代表输入的M串字符串，N代表输出的每串字符串的位数，不够补0。例如：输入2,8， “abc” ，“123456789”，则输出为“abc00000”,“12345678“,”90000000”

public class FenJieString {
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		System.out.println("请输入N的值：");
		Scanner input_n = new Scanner(System.in);
		int n = input_n.nextInt();
		System.out.println("请输入两个字符串：");
		Scanner input_01 = new Scanner(System.in);
		String in01 = input_01.nextLine();
		StringBuffer sb_01 = new StringBuffer();
		sb_01.append(in01);
		Scanner input_02 = new Scanner(System.in);
		String in02 = input_02.nextLine();
		StringBuffer sb_02 = new StringBuffer();
		sb_02.append(in02);
		fenjie(sb_01, n);
		fenjie(sb_02, n);
	}

	public static void fenjie(StringBuffer sb, int n) {
		StringBuffer sbfin = new StringBuffer();
		int m = 0;
		if (sb.length() <= n) {
			m = n - sb.length(); // 那个这里一定要用单独的变量记录长度
			for (int i = 0; i ) {
				sb.append("0");
			}
			sbfin.append(sb);
		} else {
			System.out.println(sb.toString().substring(0, n));
			sbfin.append(sb.toString().substring(n, sb.length()));
			m = n - sbfin.length();
			for (int i = 0; i ) {
				sbfin.append('0');
			}
		}
		System.out.println(sbfin);
	}
}

public class FenJieString {
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		System.out.println("请输入N的值：");
		Scanner input_n = new Scanner(System.in);
		int n = input_n.nextInt();
		System.out.println("请输入两个字符串：");
		Scanner input_01 = new Scanner(System.in);
		String in01 = input_01.nextLine();
		Scanner input_02 = new Scanner(System.in);
		String in02 = input_02.nextLine();
		fenjie(in01, n);
		fenjie(in02, n);
	}

	public static void fenjie(String sb, int n) {
		int m = 0;
		if (sb.length() <= n) {
			m = n - sb.length();
			String s = sb;
			System.out.println(s + String.format("%0" + m + "d", 0));
		} else {
			String s = sb.substring(0, n);
			System.out.println(s);
			String t = sb.substring(n, sb.length());
			m = n - t.length();
			System.out.println(t + String.format("%0" + m + "d", 0));
		}
	}
}